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目录
最近必要做一个围棋识别的项目,首先要将棋盘位置定位出来,效果图如下:
效果图
原图
中间处理效果
最终结果
思路分析
我们使用python opencv的相关函数进行操纵实现,根据棋盘颜色的特性,寻找到相关特性,将棋盘区域抠出来。最好从原始图像中将棋盘位置截取出来。
源码:定位棋盘位置
[code]from PIL import ImageGrabimport numpy as npimport cv2from glob import globimglist = sorted(glob("screen/*.jpg"))for i in imglist:# while 1: img = cv2.imread(i) image = img.copy() w,h,c = img.shape img2 = np.zeros((w,h,c), np.uint8) img3 = np.zeros((w,h,c), np.uint8) # img = ImageGrab.grab() #bbox specifies specific region (bbox= x,y,width,height *starts top-left) hsv=cv2.cvtColor(img,cv2.COLOR_BGR2HSV) lower = np.array([10,0,0]) upper = np.array([40,255,255]) mask = cv2.inRange(hsv,lower,upper) erodeim = cv2.erode(mask,None,iterations=2) # 腐蚀 dilateim = cv2.dilate(erodeim,None,iterations=2) img = cv2.bitwise_and(img,img,mask=dilateim) frame = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY) ret, dst = cv2.threshold(frame, 100, 255, cv2.THRESH_BINARY) contours,hierarchy = cv2.findContours(dst, cv2.RETR_LIST, cv2.CHAIN_APPROX_SIMPLE) cv2.imshow("0",img) i = 0 maxarea = 0 nextarea = 0 maxint = 0 for c in contours: if cv2.contourArea(c)>maxarea: maxarea = cv2.contourArea(c) maxint = i i+=1 #多边形拟合 epsilon = 0.02*cv2.arcLength(contours[maxint],True) if epsilonmaxarea: maxarea = cv2.contourArea(c) maxint = i i+=1 #多边形拟合 epsilon = 0.02*cv2.arcLength(contours[maxint],True) if epsilon |
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